捕获

闭包本质上是灵活的，并且会根据功能需要执行操作，而无需注释。这使得捕获可以灵活地适应用例，有时移动，有时借用。闭包可以捕获变量

• 通过引用：&T
• 通过可变引用：&mut T
• 通过值：T

它们优先通过引用捕获变量，并且仅在需要时才降低级别。

fn main() {
    use std::mem;
    
    let color = String::from("green");

    // A closure to print `color` which immediately borrows (`&`) `color` and
    // stores the borrow and closure in the `print` variable. It will remain
    // borrowed until `print` is used the last time. 
    //
    // `println!` only requires arguments by immutable reference so it doesn't
    // impose anything more restrictive.
    let print = || println!("`color`: {}", color);

    // Call the closure using the borrow.
    print();

    // `color` can be borrowed immutably again, because the closure only holds
    // an immutable reference to `color`. 
    let _reborrow = &color;
    print();

    // A move or reborrow is allowed after the final use of `print`
    let _color_moved = color;


    let mut count = 0;
    // A closure to increment `count` could take either `&mut count` or `count`
    // but `&mut count` is less restrictive so it takes that. Immediately
    // borrows `count`.
    //
    // A `mut` is required on `inc` because a `&mut` is stored inside. Thus,
    // calling the closure mutates `count` which requires a `mut`.
    let mut inc = || {
        count += 1;
        println!("`count`: {}", count);
    };

    // Call the closure using a mutable borrow.
    inc();

    // The closure still mutably borrows `count` because it is called later.
    // An attempt to reborrow will lead to an error.
    // let _reborrow = &count; 
    // ^ TODO: try uncommenting this line.
    inc();

    // The closure no longer needs to borrow `&mut count`. Therefore, it is
    // possible to reborrow without an error
    let _count_reborrowed = &mut count; 

    
    // A non-copy type.
    let movable = Box::new(3);

    // `mem::drop` requires `T` so this must take by value. A copy type
    // would copy into the closure leaving the original untouched.
    // A non-copy must move and so `movable` immediately moves into
    // the closure.
    let consume = || {
        println!("`movable`: {:?}", movable);
        mem::drop(movable);
    };

    // `consume` consumes the variable so this can only be called once.
    consume();
    // consume();
    // ^ TODO: Try uncommenting this line.
}

在竖线前使用 move 会强制闭包获取捕获变量的所有权

fn main() {
    // `Vec` has non-copy semantics.
    let haystack = vec![1, 2, 3];

    let contains = move |needle| haystack.contains(needle);

    println!("{}", contains(&1));
    println!("{}", contains(&4));

    // println!("There're {} elements in vec", haystack.len());
    // ^ Uncommenting above line will result in compile-time error
    // because borrow checker doesn't allow re-using variable after it
    // has been moved.
    
    // Removing `move` from closure's signature will cause closure
    // to borrow _haystack_ variable immutably, hence _haystack_ is still
    // available and uncommenting above line will not cause an error.
}

另请参阅

Box 和 std::mem::drop