if let
在某些使用场景中,当匹配枚举时,match
会显得笨拙。例如:
#![allow(unused)] fn main() { // Make `optional` of type `Option<i32>` let optional = Some(7); match optional { Some(i) => println!("This is a really long string and `{:?}`", i), _ => {}, // ^ Required because `match` is exhaustive. Doesn't it seem // like wasted space? }; }
对于这种情况,if let
更简洁,并且允许指定各种失败时的处理选项。
fn main() { // All have type `Option<i32>` let number = Some(7); let letter: Option<i32> = None; let emoticon: Option<i32> = None; // The `if let` construct reads: "if `let` destructures `number` into // `Some(i)`, evaluate the block (`{}`). if let Some(i) = number { println!("Matched {:?}!", i); } // If you need to specify a failure, use an else: if let Some(i) = letter { println!("Matched {:?}!", i); } else { // Destructure failed. Change to the failure case. println!("Didn't match a number. Let's go with a letter!"); } // Provide an altered failing condition. let i_like_letters = false; if let Some(i) = emoticon { println!("Matched {:?}!", i); // Destructure failed. Evaluate an `else if` condition to see if the // alternate failure branch should be taken: } else if i_like_letters { println!("Didn't match a number. Let's go with a letter!"); } else { // The condition evaluated false. This branch is the default: println!("I don't like letters. Let's go with an emoticon :)!"); } }
同样,if let
可以用来匹配任何枚举值。
// Our example enum enum Foo { Bar, Baz, Qux(u32) } fn main() { // Create example variables let a = Foo::Bar; let b = Foo::Baz; let c = Foo::Qux(100); // Variable a matches Foo::Bar if let Foo::Bar = a { println!("a is foobar"); } // Variable b does not match Foo::Bar // So this will print nothing if let Foo::Bar = b { println!("b is foobar"); } // Variable c matches Foo::Qux which has a value // Similar to Some() in the previous example if let Foo::Qux(value) = c { println!("c is {}", value); } // Binding also works with `if let` if let Foo::Qux(value @ 100) = c { println!("c is one hundred"); } }
另一个好处是,if let
允许我们匹配未参数化的枚举变体。即使在枚举没有实现或派生 PartialEq
的情况下也是如此。在这样的情况下,if Foo::Bar == a
会编译失败,因为枚举的实例不能被比较,但是 if let
仍然可以工作。
你想接受一个挑战吗?修改下面的示例以使用 if let
// This enum purposely neither implements nor derives PartialEq. // That is why comparing Foo::Bar == a fails below. enum Foo {Bar} fn main() { let a = Foo::Bar; // Variable a matches Foo::Bar if Foo::Bar == a { // ^-- this causes a compile-time error. Use `if let` instead. println!("a is foobar"); } }